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0=-0.5x^2+40x-15300
We move all terms to the left:
0-(-0.5x^2+40x-15300)=0
We add all the numbers together, and all the variables
-(-0.5x^2+40x-15300)=0
We get rid of parentheses
0.5x^2-40x+15300=0
a = 0.5; b = -40; c = +15300;
Δ = b2-4ac
Δ = -402-4·0.5·15300
Δ = -29000
Delta is less than zero, so there is no solution for the equation
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